A) \[{{10}^{-8}}m\]
B) \[{{10}^{-6}}m\]
C) \[{{10}^{-4}}m\]
D) \[{{10}^{-2}}m\]
Correct Answer: B
Solution :
Radius of watchglass= 10 cm \[\Rightarrow \] surface area \[=\pi {{r}^{2}}=3\times {{(10\,cm)}^{2}}\] \[=300\,c{{m}^{2}}\] mass of fatty acid in 10 ml solution \[=\frac{10\times 0.27}{100}=0.027gm\] volume of fatty acid \[=\frac{0.027}{0.9g/ml}=0.03c{{m}^{3}}\] \[\Rightarrow \]\[Height=\frac{volume\,of\,fatty\,acid}{surface\,area\,of\,watch\ glass}\] \[=\frac{0.03\,c{{m}^{3}}}{300\,c{{m}^{2}}}=0.0001cm={{10}^{-6}}m\]
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