Solved papers for JEE Main & Advanced JEE Main Paper (Held On 12 April 2014)

done JEE Main Paper (Held On 12 April 2014) Total Questions - 2

• question_answer1) Interference pattern is observed at 'P' due to superimposition of two rays coming out from a source 'S' as shown in the figure. The value of 'l' for which maxima is obtained at 'P' is: (R is perfect reflecting surface)   [JEE Main Online Paper ( Held On 12 Apirl  2014 )
  A)
  \[1=\frac{1n\lambda }{\sqrt{3}-1}\]                        
  done clear
  B)
  \[1=\frac{(2n-1)\lambda }{2\left( \sqrt{3}-1 \right)}\]
  done clear
  C)
  \[1=\frac{(2n-1)\lambda \sqrt{3}}{4\left( 2-\sqrt{3} \right)}\]     
  done clear
  D)
  \[1=\frac{(2n-1)\lambda }{\sqrt{3}-1}\]
  done clear
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• question_answer2) In an experiment of single slit diffraction pattern, first minimum for red light coincides with first maximum of some other wavelength. If wavelength of red light is \[\text{6600}\overset{\text{o}}{\mathop{\text{A}}}\,\], then wavelength of first maximum will be:   [JEE Main Online Paper ( Held On 12 Apirl  2014 )
  A)
  \[\text{3300}\overset{\text{o}}{\mathop{\text{A}}}\,\]
  done clear
  B)
  \[\text{4400}\overset{\text{o}}{\mathop{\text{A}}}\,\]
  done clear
  C)
  \[\text{5500}\overset{\text{o}}{\mathop{\text{A}}}\,\]
  done clear
  D)
  \[\text{6600}\overset{\text{o}}{\mathop{\text{A}}}\,\]
  done clear
  View Answer play_arrow