Solved papers for JEE Main & Advanced AIEEE Solved Paper-2007

done AIEEE Solved Paper-2007 Total Questions - 1

• question_answer1) In a Young's double-slit experiment, the intensity at a point where the path difference is\[=\frac{T}{4}=\frac{2}{4}=0.5s\] (\[\pi /2\]being the wavelength of the light used), is\[{{v}_{a}}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{({{10}^{-3}})}{OA}\]. If\[=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{({{10}^{-3}})}{\sqrt{{{(\sqrt{2})}^{2}}+{{(\sqrt{2})}^{2}}}}\]denotes the maximum intensity, \[{{V}_{B}}=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{({{10}^{-3}})}{OB}\]is equal to       AIEEE  Solved  Paper-2007
  A)
   \[=\frac{1}{4\pi {{\varepsilon }_{0}}}.\frac{({{10}^{-3}})}{2}\]                     
  done clear
  B)
          \[{{V}_{A}}-{{V}_{B}}=0\]                           
  done clear
  C)
          \[=\frac{\frac{1}{2}qV}{qV}=\frac{1}{2}\]                            
  done clear
  D)
          \[I={{I}_{0}}(1-{{e}^{-t/\tau }})\]
  done clear
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