Solved papers for JEE Main & Advanced AIEEE Solved Paper-2012

done AIEEE Solved Paper-2012 Total Questions - 1

• question_answer1) A liquid in a beaker has temperature \[\theta (t)\] at time t and \[{{\theta }_{0}}\] is temperature of surroundings, then according to Newton's law of cooling the correct graph between \[{{\log }_{e}}(\theta -{{\theta }_{0}})\] and t is :   AIEEE  Solved  Paper-2012
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