Solved papers for JEE Main & Advanced JEE Main Solved Paper-2015

done JEE Main Solved Paper-2015 Total Questions - 3

• question_answer1) A pendulum made of a uniform wire of cross sectional area A has time period T. When an additional mass M is added to its bob, the time period change to \[{{T}_{M}}.\]If the Young's modulus of the material of the wire is Y then\[\frac{1}{Y}\]is equal to : (g = gravitational acceleration) [JEE Main Solved Paper-2015 ]
  A)
   \[\left[ 1-{{\left( \frac{{{T}_{M}}}{T} \right)}^{2}} \right]\frac{A}{Mg}\]
  done clear
  B)
   \[\left[ 1-{{\left( \frac{T}{{{T}_{M}}} \right)}^{2}} \right]\frac{A}{Mg}\]
  done clear
  C)
  \[\left[ {{\left( \frac{{{T}_{M}}}{T} \right)}^{2}}-1 \right]\frac{A}{Mg}\] 
  done clear
  D)
  \[\left[ {{\left( \frac{{{T}_{M}}}{T} \right)}^{2}}-1 \right]\frac{Mg}{A}\]
  done clear
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• question_answer2) For a simple pendulum, a graph is plotted between its kinetic energy (KE) and potential energy (PE) against its displacement d. Which one of the following represents these correctly? (graph are schematic and not drawn to scale) [JEE Main Solved Paper-2015 ]
  A)
                                                 
  done clear
  B)
  
  done clear
  C)
                                                 
  done clear
  D)
  
  done clear
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• question_answer3) The period of oscillation of a simple pendulum is \[T=2\pi \sqrt{\frac{L}{g}}.\]Measured value of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 90 s using a wrist watch of 1s resolution. The accuracy in the determination of g is : [JEE Main Solved Paper-2015 ]
  A)
  1%                                         
  done clear
  B)
  5%
  done clear
  C)
  2%                                         
  done clear
  D)
  3%
  done clear
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