Solved papers for JEE Main & Advanced JEE Main Paper (Held On 9 April 2016)

done JEE Main Paper (Held On 9 April 2016)

• question_answer1) Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to A and T, respectively. At time t = 0 one particle has displacement A while the other one has displacement $\frac{-A}{2}$and they are moving towards each other If they cross each at time t, then t is :   JEE Main Online Paper (Held On 09 April 2016)

A) $\frac{T}{4}$

B) $\frac{5T}{6}$

C) $\frac{T}{3}$

D) $\frac{T}{6}$