Solved papers for JEE Main & Advanced JEE Main Paper (Held On 25 April 2013)

done JEE Main Paper (Held On 25 April 2013) Total Questions - 1

• question_answer1)                 A ring of mass M and radius R is rotating about its axis with angular velocity \[\omega \]. Two identical bodies each of mass m are now gently attached at the two ends of a diameter of the ring. Because of this, the kinetic energy loss will be :     JEE Main Online Paper ( Held On 25  April 2013 )
  A)
                  \[\frac{\operatorname{m}(\operatorname{M}+2m)}{\operatorname{M}}{{\omega }^{2}}{{R}^{2}}\]    
  done clear
  B)
                                         \[\frac{\operatorname{Mm}}{(\operatorname{M}+m)}{{\omega }^{2}}{{R}^{2}}\]
  done clear
  C)
                                         \[\frac{\operatorname{Mm}}{(\operatorname{M}+2m)}{{\omega }^{2}}{{R}^{2}}\]       
  done clear
  D)
                                         (d)\[\frac{\left( \operatorname{M}+m \right)\operatorname{M}}{(\operatorname{M}+2m)}{{\omega }^{2}}{{R}^{2}}\]
  done clear
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