Solved papers for JEE Main & Advanced JEE Main Online Paper (Held On 23 April 2013)

done JEE Main Online Paper (Held On 23 April 2013) Total Questions - 1

• question_answer1) Electrons are accelerated through a potentialdifference V and protons are acceleratedthrough a potential difference 4 V. The de-Broglie wavelengths are  \[{{\lambda }_{e}}\] and \[{{\lambda }_{\operatorname{p}}}\] for electrons and protons respectively. The ratio of \[\frac{{{\lambda }_{e}}}{{{\lambda }_{\operatorname{P}}}}\] is given by: (given\[{{\operatorname{m}}_{e}}\]is mass of electron and\[{{\operatorname{m}}_{\operatorname{p}}}\]is mass of proton)     [JEE Main Online Paper ( Held On 23  April 2013 )
  A)
   \[\frac{{{\lambda }_{e}}}{{{\lambda }_{\operatorname{P}}}}=\sqrt{\frac{{{\operatorname{m}}_{\operatorname{p}}}}{{{\operatorname{m}}_{\operatorname{e}}}}}\]                               
  done clear
  B)
                                          \[\frac{{{\lambda }_{e}}}{{{\lambda }_{\operatorname{P}}}}=\sqrt{\frac{{{\operatorname{m}}_{e}}}{{{\operatorname{m}}_{\operatorname{P}}}}}\]
  done clear
  C)
                                          \[\frac{{{\lambda }_{e}}}{{{\lambda }_{\operatorname{P}}}}=\frac{1}{2}\sqrt{\frac{{{\operatorname{m}}_{e}}}{{{\operatorname{m}}_{\operatorname{P}}}}}\]               
  done clear
  D)
                                          \[\frac{{{\lambda }_{e}}}{{{\lambda }_{\operatorname{P}}}}=2\sqrt{\frac{{{\operatorname{m}}_{\operatorname{P}}}}{{{\operatorname{m}}_{e}}}}\]
  done clear
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