Solved papers for JEE Main & Advanced AIEEE Solved Paper-2009

done AIEEE Solved Paper-2009 Total Questions - 2

• question_answer1) Directions Q. Nos. 12 are based on the following paragraph. A current loop ABCD is held fixed on the plane of the paper as shown in the figure. The arcs BC (radius =b) and DA (radius = a) of the loop are joined by the straight wires AB and CD. A steady current  is flowing in the loop. Angle made by A B and CD at the origin O is 30°. Another straight thin wire with steady current  flowing out of the plane of the paper is kept at the origin.   The magnitude of the magnetic field (B) due to the loop ABCD at the origin (O) is   AIEEE  Solved  Paper-2009  
  A)
  zero
  done clear
  B)
  \[\frac{{{\mu }_{0}}I(b-a)}{24ab}\]
  done clear
  C)
  \[\frac{{{\mu }_{0}}I}{4\pi }\left[ \frac{b-a}{ab} \right]\]
  done clear
  D)
  \[\frac{{{\mu }_{0}}I}{4\pi }\left[ 2(b\_a)+\frac{\pi }{3}(a+b) \right]\]
  done clear
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• question_answer2) Directions Q. Nos. 13 are based on the following paragraph. A current loop ABCD is held fixed on the plane of the paper as shown in the figure. The arcs BC (radius =b) and DA (radius = a) of the loop are joined by the straight wires AB and CD. A steady current \[I\] is flowing in the loop. Angle made by A B and CD at the origin O is 30°. Another straight thin wire with steady current \[{{I}_{2}}\] flowing out of the plane of the paper is kept at the origin. Due to the presence of the current \[{{I}_{1}}\] at the origin:     AIEEE  Solved  Paper-2009
  A)
  the forces on AB and DC are zero
  done clear
  B)
  the forces on AD and BC are zero
  done clear
  C)
  the magnitude of the net force on the loop is given by\[\frac{{{I}_{1}}I}{4\pi }{{\mu }_{0}}\left[ 2(b-a)+\frac{\pi }{3}(a+b) \right]\]
  done clear
  D)
  the magnitude of the net force on the loop is given by\[\frac{{{\mu }_{0}}I{{I}_{1}}}{24ab}(b-a)\]
  done clear
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