Solved papers for JEE Main & Advanced JEE Main Solved Paper-2015
done JEE Main Solved Paper-2015 Total Questions - 1
question_answer1) From a solid sphere of mass M and radius R, a spherical portion of radius \[\frac{R}{2}\]is removed, as shown in the figure. Taking gravitional potential V = 0 at \[r=\infty ,\] the potential at the centre of cavity thus formed is: (G = gravitational constant)
[JEE Main Solved Paper-2015 ]