Solved papers for JEE Main & Advanced AIEEE Solved Paper-2009

done AIEEE Solved Paper-2009 Total Questions - 1

• question_answer1) The height at which the acceleration due to gravity becomes\[\frac{g}{9}\](where g = the acceleration due to gravity on the surface of the earth) in terms of R, the radius of the earth, is:     AIEEE  Solved  Paper-2009
  A)
  2R                                          
  done clear
  B)
  \[\frac{R}{\sqrt{2}}\]                     
  done clear
  C)
         R/2                        
  done clear
  D)
         \[\sqrt{2}R\]
  done clear
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