Solved papers for JEE Main & Advanced JEE Main Paper (Held On 19 April 2014)

done JEE Main Paper (Held On 19 April 2014) Total Questions - 2

  • question_answer1) The electric field in a region of space is given by, \[\vec{E}={{E}_{o}}\hat{i}+2{{E}_{o}}\hat{j}\]where \[{{E}_{o}}=100N/C.\]The flux of the field through a circular surface of radius 0.02 m parallel to the YZ plane is nearly:     JEE Main Online Paper (Held On 19 April 2016)

    A)
    0.125 Nm2/C     

    B)
    0.02 Nm2/C

    C)
    0.005 Nm2/C     

    D)
    3.14 Nm2/C

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  • question_answer2) The gap between the plates of a parallel plate capacitor of area A and distance between plates d, is filled with a dielectric whose permittivity varies linearly from \[{{\in }_{1}}\] at one plate to \[{{\in }_{2}}\]at the other. The capacitance of capacitor is:     JEE Main Online Paper (Held On 19 April 2016)

    A)
    \[{{\in }_{0}}\left( {{\in }_{1}}+{{\in }_{2}} \right)A/d\]   

    B)
    \[{{\in }_{0}}\left( {{\in }_{2}}+{{\in }_{1}} \right)A/2d\]

    C)
    \[{{\in }_{0}}A/\left[ d/n\left( {{\in }_{2}}+{{\in }_{1}} \right) \right]\]

    D)
    \[{{\in }_{0}}A/\left( {{\in }_{2}}-{{\in }_{1}} \right)A/\left[ d/n\left( {{\in }_{2}}/{{\in }_{1}} \right) \right]\]

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JEE Main Online Paper (Held On 19 April 2014)
 

   


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