Solved papers for JEE Main & Advanced JEE Main Online Paper (Held on 9 April 2013)

done JEE Main Online Paper (Held on 9 April 2013) Total Questions - 4

• question_answer1)                                   A uniform electric field \[\vec{E}\] exists between the plates of a charged condenser. A charged particle enters the space between the plates and perpendicular to \[\vec{E}\]. The path of the particle between the plates is a:                     JEE Main Online Paper (Held On 09 April 2013)
  A)
                  straight line                                       
  done clear
  B)
                  hyperbola                                          
  done clear
  C)
                  parabola                                             
  done clear
  D)
                  circle                
  done clear
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• question_answer2)                 Two point dipoles of dipole moment \[\overset{\to }{\mathop{{{\operatorname{P}}_{1}}}}\,\] and \[\overset{\to }{\mathop{{{\operatorname{P}}_{2}}}}\,\] are at a distance \[x\] from each other and \[\overset{\to }{\mathop{{{\operatorname{P}}_{2}}}}\,||\overset{\to }{\mathop{{{\operatorname{P}}_{2}}}}\,\]. The force between the dipoles is:                   JEE Main Online Paper (Held On 09 April 2013)
  A)
                  \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{4{{\operatorname{p}}_{1}}{{\operatorname{p}}_{2}}}{{{x}^{4}}}\]                
  done clear
  B)
                  \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{3{{\operatorname{p}}_{1}}{{\operatorname{p}}_{2}}}{{{x}^{3}}}\]                               
  done clear
  C)
                  \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{6{{\operatorname{p}}_{1}}{{\operatorname{p}}_{2}}}{{{x}^{4}}}\]                
  done clear
  D)
                  \[\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{8{{\operatorname{p}}_{1}}{{\operatorname{p}}_{2}}}{{{x}^{4}}}\]                
  done clear
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• question_answer3)                 Two balls of same mass and carrying equal charge are hung from a fixed support of length \[l\]. At electrostatic equilibrium, assuming that angles made by each thread is small, the separation, \[x\] between the balls is proportional to :       JEE Main Online Paper (Held On 09 April 2013)            
  A)
                  \[l\]                                                       
  done clear
  B)
                  \[{{l}^{2}}\]                                                        
  done clear
  C)
                  \[{{l}^{2/3}}\]                
  done clear
  D)
                  \[{{l}^{1/3}}\]                
  done clear
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• question_answer4)                 From the following, the quantity (constructed from the basic constants of nature), that has the dimensions, as well as correct order of magnitude, vis-a-vis typical atomic size, is:                   JEE Main Online Paper (Held On 09 April 2013)
  A)
                  \[\frac{{{e}^{2}}}{4\pi {{\varepsilon }_{0}}\,m{{c}^{2}}}\]                                             
  done clear
  B)
                  \[\frac{4\pi {{\varepsilon }_{0}}\,{{b}^{2}}}{m{{e}^{2}}}\]                             
  done clear
  C)
                         \[\frac{m{{c}^{2}}}{4\pi {{\varepsilon }_{0}}\,{{b}^{2}}}\]                                             
  done clear
  D)
                  \[\frac{4\pi {{\varepsilon }_{0}}\,m{{c}^{2}}}{{{e}^{2}}}\]                
  done clear
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