Solved papers for JEE Main & Advanced JEE Main Paper (Held On 25 April 2013)
done JEE Main Paper (Held On 25 April 2013) Total Questions - 3
question_answer1) This question has Statement-1 and that Statements-2. Of the four choice given after the Statements, choose the one that best describes the two Statements. Statement 1: No work is required to be done to move a fest charge between any two pints on an equipotential surface. Statement 2: Electric lines of force at the equipotential surfaces are mutually perpendicular to each other
JEE Main Online Paper ( Held On 25 April 2013 )
A)
Statement 1 is true, Statement 2 is true, Statement 2 is the correct explanation of Statement 1
doneclear
B)
Statement 1 is true, Statement 2 is true, Statement 2 is not the correct explanation of Statement 1.
question_answer2) The surface charge density of a thin charge disc of radius R is \[\sigma \]. The value of the electric field at the centre of the disc is \[\frac{\sigma }{2{{\in }_{0}}}.\]With respect to the field at the centre, the electric field along the axis at a distance R From the centre of the disc:
JEE Main Online Paper ( Held On 25 April 2013 )
question_answer3) A parallel plate capacitor having a separation between the plates d, plate area A and material with dielectric constant K has capacitance \[{{C}_{0}}\]. Now one-third of the materialism replaced by another material with dielectric constant 2K, so that effectively there are two capacitors one with area \[\frac{1}{3}\operatorname{A},\] dielectric constant 2 K and another with area \[\frac{2}{3}\operatorname{A},\]and dielectric constant K. If the capacitance of this new capacitor is C then \[C/{{C}_{0}}\]is:
JEE Main Online Paper ( Held On 25 April 2013 )