Solved papers for JEE Main & Advanced JEE Main Paper (Held On 11 April 2014)

done JEE Main Paper (Held On 11 April 2014) Total Questions - 2

• question_answer1) A cone of base radius R and height h is located in a uniform electric field \[\overset{\to }{\mathop{E}}\,\] parallel to its base. The electric flux entering the cone is:   [JEE Main Online Paper ( Held On 11 Apirl  2014 )
  A)
  \[\frac{1}{2}EhR\]                           
  done clear
  B)
  her
  done clear
  C)
  2 E h R  
  done clear
  D)
  4 E h R
  done clear
  View Answer play_arrow

• question_answer2) A parallel plate capacitor is made of two plates of length l, width w and separated by distance d. A dielectric slab (dielectric constant K) that fits exactly between the plates is held near the edge of the plates. It is pulled into the capacitor by a force\[F=-\frac{\partial U}{\partial x}\]where U is the energy of the capacitor when dielectric is inside the capacitor up to distance x (See figure). If the charge on the capacitor is Q then the force on the dielectric when it is near the edge is:   [JEE Main Online Paper ( Held On 11 Apirl  2014 )
  A)
  \[\frac{{{Q}^{2}}d}{2\omega {{1}^{2}}{{\varepsilon }_{o}}}K\]                    
  done clear
  B)
  \[\frac{{{Q}^{2}}\omega }{2d{{1}^{2}}{{\varepsilon }_{o}}}\left( K-1 \right)\]
  done clear
  C)
  \[\frac{{{Q}^{2}}d}{2w{{1}^{2}}{{\varepsilon }_{o}}}\left( K-1 \right)\]   
  done clear
  D)
  \[\frac{{{Q}^{2}}w}{2d{{1}^{2}}{{\varepsilon }_{o}}}K\]
  done clear
  View Answer play_arrow