Solved papers for JEE Main & Advanced AIEEE Solved Paper-2005

done AIEEE Solved Paper-2005 Total Questions - 5

• question_answer1) A fully charged capacitor has a capacitance C. It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity s and mass m. If the temperature of the block is raised by \[\Delta T,\] the potential difference V across the capacitance is     AIEEE  Solved  Paper-2005
  A)
  \[\sqrt{\frac{2mC\Delta T}{s}}\]               
  done clear
  B)
         \[\frac{mC\Delta T}{s}\]               
  done clear
  C)
         \[\frac{ms\Delta T}{C}\]               
  done clear
  D)
         \[\sqrt{\frac{2ms\Delta T}{C}}\]
  done clear
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• question_answer2) A charged ball B hangs from a silk thread S, which makes an angle \[\theta \] with a large charged conducting sheet as shown in the figure. The surface charge density \[\sigma \] of the sheet is proportional to   AIEEE  Solved  Paper-2005
  A)
  \[\cos \theta \]
  done clear
  B)
                         \[\cot \theta \]
  done clear
  C)
                         \[\sin \theta \]                 
  done clear
  D)
         \[\tan \theta \]
  done clear
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• question_answer3) Two point charges\[+8q\]and\[-2q\]are located at\[x=0\]and\[x=L\]respectively. The location of a point on the x-axis at which the net electric field due to these two point charges is zero, is     AIEEE  Solved  Paper-2005
  A)
  2L           
  done clear
  B)
                         L/4           
  done clear
  C)
         8L                           
  done clear
  D)
         4L
  done clear
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• question_answer4) Two thin wire rings each having a radius R are placed at a distance d apart with their axes coinciding. The charges on the two rings are \[+\text{ }q\]and\[-\text{ }q\]. The potential difference between the centres of the two rings is     AIEEE  Solved  Paper-2005
  A)
  \[\frac{qR}{4\pi {{\varepsilon }_{0}}{{d}^{2}}}\]
  done clear
  B)
  \[\frac{q}{2\pi {{\varepsilon }_{0}}}\left[ \frac{1}{R}-\frac{1}{\sqrt{{{R}^{2}}+{{d}^{2}}}} \right]\]
  done clear
  C)
  zero
  done clear
  D)
  \[\frac{q}{4\pi {{\varepsilon }_{0}}}\left[ \frac{1}{R}-\frac{1}{\sqrt{{{R}^{2}}+{{d}^{2}}}} \right]\]
  done clear
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• question_answer5) A parallel plate capacitor is made by stacking  n  equally  spaced  plates connected alternatively. If the capacitance between any two adjacent plates is C, then the resultant capacitance is     AIEEE  Solved  Paper-2005
  A)
  \[(n-1)C\]       
  done clear
  B)
         \[(n+1)C\]          
  done clear
  C)
         C                            
  done clear
  D)
         \[nC\]
  done clear
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