Solved papers for JEE Main & Advanced AIEEE Solved Paper-2004

done AIEEE Solved Paper-2004 Total Questions - 3

• question_answer1) A coil having n turns and resistance\[R\,\Omega \]. is connected with a galvanometer of resistance\[4R\,\Omega \]. This combination is moved in time t seconds from a magnetic field\[{{W}_{1}}\]weber to\[{{W}_{2}}\] weber. The induced current in the circuit is
  A)
  \[\frac{{{W}_{2}}-{{W}_{1}}}{5Rnt}\]      
  done clear
  B)
         \[-\frac{n({{W}_{2}}-{{W}_{1}})}{5Rt}\]
  done clear
  C)
                         \[-\frac{({{W}_{2}}-{{W}_{1}})}{Rnt}\]   
  done clear
  D)
         \[-\frac{n({{W}_{2}}-{{W}_{1}})}{Rt}\]
  done clear
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• question_answer2) In a uniform magnetic field of induction B, a wire in the form of semi-circle, of radius r rotates about the diameter of the circle with angular frequency\[\omega \]. If the total resistance of the circuit is R, the mean power generated per period of rotation is
  A)
  \[\frac{B\pi {{r}^{2}}\omega }{2R}\]       
  done clear
  B)
         \[\frac{{{(B\pi {{r}^{2}}\omega )}^{2}}}{8R}\]     
  done clear
  C)
         \[\frac{{{(B\pi r\omega )}^{2}}}{2R}\]    
  done clear
  D)
         \[\frac{{{(B\pi r{{\omega }^{2}})}^{2}}}{8R}\]
  done clear
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• question_answer3) A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 rad/s. If the horizontal component of the earth's magnetic field is\[0.2\times {{10}^{-4}}T\]then the emf developed between the two ends of the conductor is
  A)
  \[5\mu V\]   
  done clear
  B)
                         \[50\mu V\]      
  done clear
  C)
         \[5mV\]              
  done clear
  D)
         \[50\,mV\]
  done clear
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