Solved papers for JEE Main & Advanced JEE Main Paper (Held On 26 May 2012)
done JEE Main Paper (Held On 26 May 2012) Total Questions - 2
question_answer1) The resistance of a wire is R. It is bent at the middle by 180° and both the ends are twisted together to make a shorter wire. The resistance of the new wire is
JEE Main Online Paper (Held On 26-May-2012)
question_answer2) In an experiment of potentiometer for measuring the internal resistance of primary cell a balancing length \[\ell \]is obtained on the potentiometer wire when the cell is open circuit. Now the cell is short circuited by a resistance R, If R is to be equal to the internal resistance of the cell the balancing length on the potentiometer wire will be.
JEE Main Online Paper (Held On 26-May-2012)