Solved papers for JEE Main & Advanced JEE Main Paper (Held On 10 April 2016)

done JEE Main Paper (Held On 10 April 2016) Total Questions - 3

• question_answer1) A galvanometer has a 50 division scale. Battery has no internal resistance. It is found that there is deflection of 40 divisions when \[R=2400\,\,\Omega \].Deflection becomes 20 divisions when resistance taken form resistance box is\[4900\,\,\,\Omega \]. Then we can conclude:   JEE Main Online Paper (Held On 10 April 2016)
  A)
  Resistance required on R.B. For a deflection of 10 divisions is \[9800\,\,\,\Omega \].                
  done clear
  B)
  Full scale deflection current is 2 mA.                
  done clear
  C)
  Current sensitivity of galvanometer is \[20\mu A/\] division.                
  done clear
  D)
  Resistance of galvanometer is \[200\,\,\Omega \]
  done clear
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• question_answer2) A particle of mass M is moving in a circle of fixed radius R in such a way that its centripetal acceleration at time t is given by \[{{n}^{2}}R\,{{t}^{2}}\]where n is a constant. The power delivered to the particle by the force acting on it, is:   JEE Main Online Paper (Held On 10 April 2016)
  A)
  \[M\,\,n\,{{R}^{2}}\,{{t}^{2}}\]                    
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  B)
  \[\frac{1}{2}M{{n}^{2}}{{R}^{2}}{{t}^{2}}\]
  done clear
  C)
  \[M\,{{n}^{2}}{{R}^{2}}t\]                              
  done clear
  D)
  \[M\,n\,{{R}^{2}}\,t\]
  done clear
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• question_answer3) The resistance of an electrical toaster has a temperature dependence given by \[R\,\,(T)={{R}_{0}}[1+\alpha (T-{{T}_{0}}]\]in its range of operation. At \[{{T}_{0}}=300\,K,\,R=100\Omega \]. And at\[T=500\,K,\,R=120\Omega \]. The toaster is connected to a voltage source at 200 V and its temperature is raised at a constant rate form300 to 500 K in 30s. The total work done in raising the temperature is:   JEE Main Online Paper (Held On 10 April 2016)
  A)
  \[400\,In\frac{1.5}{1.3}J\]                               
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  B)
   300 J
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  C)
  \[200\,In\frac{2}{3}J\]                      
  done clear
  D)
  \[400\,In\frac{5}{6}J\]
  done clear
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