Solved papers for JEE Main & Advanced AIEEE Solved Paper-2003
done AIEEE Solved Paper-2003 Total Questions - 9
question_answer1) The length of a wire of a potentiometer is 100 cm and the emf of its stand and cell is. E volt. It is employed to measure the emf of a battery whose internal resistance is \[0.5\,\,\Omega \]. If the balance point is obtained at \[1=30\] cm from the positive end, the emf of the battery is
AIEEE Solved Paper-2003
A)
\[\frac{30\,E}{100.5}\]
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B)
\[\frac{30\,E}{100-05}\]
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C)
\[\frac{30\,(E-0.5i)}{100}\], where \[i\] is the current in the potentiometer wire
question_answer3) The thermo-emf of a thermocouple is \[25\mu V{{/}^{o}}C\] at room temperature. A galvanometer of \[40\,\Omega \]. resistance, capable of detecting current as low as \[{{10}^{-5}}\] A, is connected with the thermocouple. The smallest temperature difference that can be detected by this system is
AIEEE Solved Paper-2003
question_answer4) The negative Zn-pole of Daniell cell, sending a constant current through a circuit, decreases in mass by \[0.13\]g in 30 min. If the electrochemical equivalent of Zn and Cu are \[32.5\] and \[31.5\] respectively, the increase in the mass of the positive Cu-pole in this time is
AIEEE Solved Paper-2003
question_answer5) The difference in the variation of resistance with temperature in a metal and a semiconductor arises essentially due to the difference in the
AIEEE Solved Paper-2003
A)
crystal structure
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B)
variation of the number of charge carriers with temperature
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C)
type of bonding
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D)
variation of scattering mechanism with temperature
question_answer6) An ammeter reads upto 1 A. Its internal resistance is \[0.81\,\,\Omega \]. To increase the range to 10 A, the value of the required shunt is
AIEEE Solved Paper-2003
question_answer7) A 3 V battery with negligible internal resistance is connected in a circuit as shown in the figure. The current I, in the circuit will be
AIEEE Solved Paper-2003
question_answer9) The length of a given cylindrical wire is increased by \[100%\]. Due to the consequent decrease in diameter, the change in the resistance of the wire will be
AIEEE Solved Paper-2003