Solved papers for JEE Main & Advanced AIEEE Solved Paper-2002

done AIEEE Solved Paper-2002 Total Questions - 3

• question_answer1) The value of \[\frac{1-{{\tan }^{2}}{{15}^{o}}}{1+{{\tan }^{2}}{{15}^{o}}}\] is   AIEEE  Solved  Paper-2002
  A)
  1                
  done clear
  B)
                            \[\sqrt{3}\]                                           
  done clear
  C)
               \[\frac{\sqrt{3}}{2}\]   
  done clear
  D)
                         2
  done clear
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• question_answer2) If \[\tan \theta =-\frac{4}{3}\] then sine is   AIEEE  Solved  Paper-2002
  A)
  \[-\frac{4}{5}\] but not \[\frac{4}{5}\]    
  done clear
  B)
            \[-\frac{4}{5}\] or \[\frac{4}{5}\]
  done clear
  C)
            \[\frac{4}{5}\] but not \[-\frac{4}{5}\]  
  done clear
  D)
            None of these
  done clear
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• question_answer3) If \[\sin (\alpha +\beta )=1,\,\,\sin (\alpha -\beta )=\frac{1}{2}\] then \[\tan \,(a+2\beta )\tan \,(2\alpha +\beta )\] is equal to   AIEEE  Solved  Paper-2002
  A)
  1   
  done clear
  B)
  - 1             
  done clear
  C)
  zero                         
  done clear
  D)
  None of these
  done clear
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