Solved papers for JEE Main & Advanced JEE Main Paper (Held On 19 April 2014)

done JEE Main Paper (Held On 19 April 2014) Total Questions - 1

• question_answer1) The circumcentre of a triangle lies at the origin and its centroid is the mid point of the line segment joining the points \[({{a}^{2}}+1,{{a}^{2}}+1)\]and \[(2a,-2a),a\ne 0.\]Then for any a, the orthocentre of this triangle lies on the line:     JEE Main Online Paper (Held On 19 April 2016)
  A)
  \[y-2ax=0\]                        
  done clear
  B)
  \[y-({{a}^{2}}+1)x=0\]
  done clear
  C)
  \[y+x=0\]                           
  done clear
  D)
  \[{{(a-1)}^{2}}x-{{(a+1)}^{2}}y=0\]
  done clear
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