# Solved papers for JEE Main & Advanced AIEEE Solved Paper-2004

### done AIEEE Solved Paper-2004

The probability that A speaks truth is 4/5 while this probability for B is 3/4. The probability that they contradict each other when asked to speak on a fact, is

A)
$\frac{3}{20}$

B)
$\frac{1}{5}$

C)
$\frac{7}{20}$

D)
$\frac{4}{5}$

A random variable X has the probability distribution  $x$ 1 2 3 4 5 6 7 8 $p(x)$ 0.15 0.23 0.12 0.1 0.2 0.08 0.07 0.05
For the events E = {X is a prime number} and$F=\{X<4\},$the probability$P(E\cup F)$is

A)
0.87

B)
0.77

C)
0.35

D)
0.50

The mean and the variance of a binomial distribution are 4 and 2, respectively. Then, the probability of 2 successes is

A)
$\frac{37}{256}$

B)
$\frac{219}{256}$

C)
$\frac{128}{256}$

D)
$\frac{28}{256}$