Solved papers for JEE Main & Advanced AIEEE Solved Paper-2004

done AIEEE Solved Paper-2004

  • question_answer1) The probability that A speaks truth is 4/5 while this probability for B is 3/4. The probability that they contradict each other when asked to speak on a fact, is

    A) \[\frac{3}{20}\]

    B) \[\frac{1}{5}\]

    C) \[\frac{7}{20}\]

    D) \[\frac{4}{5}\]

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  • question_answer2) A random variable X has the probability distribution

    \[x\] 1 2 3 4 5 6 7 8
    \[p(x)\] 0.15 0.23 0.12 0.10 0.20 0.08 0.07 0.05
    For the events E = {X is a prime number} and\[F=\{X<4\},\]the probability\[P(E\cup F)\]is

    A) 0.87

    B) 0.77

    C) 0.35

    D) 0.50

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  • question_answer3) The mean and the variance of a binomial distribution are 4 and 2, respectively. Then, the probability of 2 successes is

    A) \[\frac{37}{256}\]

    B) \[\frac{219}{256}\]

    C) \[\frac{128}{256}\]

    D) \[\frac{28}{256}\]

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AIEEE Solved Paper-2004
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