Solved papers for JEE Main & Advanced JEE Main Solved Paper-2015

done JEE Main Solved Paper-2015 Total Questions - 1

• question_answer1) Let \[{{\tan }^{-1}}y={{\tan }^{-1}}x+{{\tan }^{-1}}\left( \frac{2x}{1-{{x}^{2}}} \right),\]where \[|x|<\frac{1}{\sqrt{3}}.\]Then a value of y is : [JEE Main Solved Paper-2015 ]
  A)
  \[\frac{3x-{{x}^{3}}}{1+3{{x}^{2}}}\]                       
  done clear
  B)
  \[\frac{3x+{{x}^{3}}}{1+3{{x}^{2}}}\]
  done clear
  C)
  \[\frac{3x-{{x}^{3}}}{1-3{{x}^{2}}}\]        
  done clear
  D)
  \[\frac{3x+{{x}^{3}}}{1-3{{x}^{2}}}\]
  done clear
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