Solved papers for JEE Main & Advanced JEE Main Paper (Held On 11 April 2014)

done JEE Main Paper (Held On 11 April 2014) Total Questions - 1

• question_answer1) The integral\[\int_{{}}^{{}}{x{{\cos }^{-1}}}\left( \frac{1-{{x}^{2}}}{1+{{x}^{2}}} \right)dx(x>0)\]is equal to:   [JEE Main Online Paper ( Held On 11 Apirl  2014 )
  A)
  \[-x+1(1+{{x}^{2}})ta{{n}^{-1}}x+c\]
  done clear
  B)
  \[x-(1+{{x}^{2}})co{{t}^{-1}}x+c\]
  done clear
  C)
  \[-x+(1+{{x}^{2}})co{{t}^{-1}}x+c\]
  done clear
  D)
  \[x-(1+{{x}^{2}})ta{{n}^{-1}}x+c\]
  done clear
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