Solved papers for JEE Main & Advanced JEE Main Paper (Held On 9 April 2016)

done JEE Main Paper (Held On 9 April 2016) Total Questions - 1

• question_answer1) Let a and b respectively be the semi-transverse and semi-conjugate axes of a hyperbola whose eccentricity satisfies the equation \[\text{9e}{{\text{-}}^{\text{2}}}\text{-18e}+\text{5}=0.\] If S(5, 0) is a focus and 5x = 9 is the corresponding directrix of hyperbola, then \[{{a}^{2}}-{{b}^{2}}\]is equal to   JEE Main Online Paper (Held On 09 April 2016)
  A)
  - 7          
  done clear
  B)
  - 5
  done clear
  C)
  5                                             
  done clear
  D)
  7
  done clear
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