Solved papers for JEE Main & Advanced AIEEE Paper (Held On 11 May 2011)

done AIEEE Paper (Held On 11 May 2011) Total Questions - 1

• question_answer1) The equation of the hyperbola whose foci are (-2, 0) and (2, 0) and eccentricity is 2 is given by:     AIEEE  Solved  Paper (Held On 11 May  2011)
  A)
  \[{{x}^{2}}-3{{y}^{2}}=3\]
  done clear
  B)
  \[3{{x}^{2}}-{{y}^{2}}=3\]
  done clear
  C)
  \[-{{x}^{2}}+3{{y}^{2}}=3\]
  done clear
  D)
  \[-3{{x}^{2}}+{{y}^{2}}=3\]
  done clear
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