Solved papers for JEE Main & Advanced JEE Main Paper (Held On 9 April 2014)

done JEE Main Paper (Held On 9 April 2014) Total Questions - 3

  • question_answer1) If equations \[a{{x}^{2}}+bx+c=0(a,b,c\in R,a\ne 0)\]and \[2{{x}^{2}}+3x+4=0\]have a common root, then a : b : c equals:   [JEE Main Online Paper ( Held On 09 Apirl  2014  )

    A)
    : 2 : 3                     

    B)
    2 : 3 : 4

    C)
    4 : 3 : 2                 

    D)
    3 : 2 : 1

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  • question_answer2) If\[\frac{1}{\sqrt{\alpha }}\]and\[\frac{1}{\sqrt{\beta }}\] are the roots of the equation,\[a{{x}^{2}}+bx+1=0\]\[(a\ne 0,a,b,\in R),\]then the equation,\[x\left( x+{{b}^{3}} \right)+\left( {{a}^{3}}-3abx \right)=0\]has roots:   [JEE Main Online Paper ( Held On 09 Apirl  2014  )

    A)
    \[{{\alpha }^{{}^{3}/{}_{2}}}\]and\[{{\beta }^{{}^{3}/{}_{2}}}\]  

    B)
    \[\alpha {{\beta }^{{}^{1}/{}_{2}}}\]and\[{{\alpha }^{{}^{1}/{}_{2}}}\beta \]

    C)
     \[\sqrt{\alpha \beta }\]and\[\alpha \beta \]      

    D)
    \[{{\alpha }^{-\frac{3}{2}}}\]and\[{{\beta }^{-\frac{3}{2}}}\]

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  • question_answer3) If \[f(x)={{\left( \frac{3}{5} \right)}^{x}}+{{\left( \frac{4}{5} \right)}^{x}}=-1,x\in R,\]then the equation f(x) =0 has :   [JEE Main Online Paper ( Held On 09 Apirl  2014  )

    A)
    no solution

    B)
    one solution

    C)
    two solutions

    D)
    more than two solutions

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Study Package

JEE Main Online Paper (Held On 9 April 2014)
 

   


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