Solved papers for JEE Main & Advanced AIEEE Solved Paper-2012

done AIEEE Solved Paper-2012 Total Questions - 2

• question_answer1) Statement-1: An equation of a common tangent to the parabola \[{{y}^{2}}=16\sqrt{3}x\] and the ellipse \[2{{x}^{2}}+{{y}^{2}}=4\] is \[y=2x+2\sqrt{3}\]. Statement-2: If the line \[mx+\frac{4\sqrt{3}}{m},(m\ne 0)\] is a common tangent to the parabola \[{{y}^{2}}=16\sqrt{3}x\] and the ellipse \[2{{x}^{2}}+{{y}^{2}}=4\], then m satisfies\[{{m}^{4}}+2{{m}^{2}}=24\].   AIEEE  Solved  Paper-2012
  A)
  Statement-1 is false, Statement-2 is true.
  done clear
  B)
  Statement-1 is true, statement-2 is true; statement-2 is a correct explanation for Statement-1.
  done clear
  C)
  Statement-1 is true, statement-2 is true; statement-2 is not a correct explanation for Statement-1.
  done clear
  D)
               Statement-1 is true, statement-2 is false.
  done clear
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• question_answer2) An ellipse is drawn by taking a diameter of the circle \[{{(x-1)}^{2}}+{{y}^{2}}=1\] as its semi-minor axis and a diameter of the circle \[{{x}^{2}}+{{(y-2)}^{2}}=4\] is semi-major axis. If the centre of the ellipse is at the origin and its axes are the coordinate axes, then the equation of the ellipse is :   AIEEE  Solved  Paper-2012
  A)
  \[4{{x}^{2}}+{{y}^{2}}=4\]                              
  done clear
  B)
  \[{{x}^{2}}+4{{y}^{2}}=8\]
  done clear
  C)
  \[4{{x}^{2}}+{{y}^{2}}=8\]                              
  done clear
  D)
  \[{{x}^{2}}+4{{y}^{2}}=16\]
  done clear
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