Solved papers for JEE Main & Advanced JEE Main Paper (Held On 9 April 2014)

done JEE Main Paper (Held On 9 April 2014) Total Questions - 1

• question_answer1) If f(x) is continuous and\[f\left( \frac{9}{2} \right)=\frac{2}{9},\]then \[\underset{x\to 0}{\mathop{\lim }}\,f\left( \frac{1-\cos 3x}{{{x}^{2}}} \right)\]is equal to:   [JEE Main Online Paper ( Held On 09 Apirl  2014  )
  A)
  \[\frac{9}{2}\]                                   
  done clear
  B)
  \[\frac{2}{9}\]
  done clear
  C)
  0                                             
  done clear
  D)
  \[\frac{8}{9}\]
  done clear
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