Solved papers for JEE Main & Advanced JEE Main Solved Paper-2016

done JEE Main Solved Paper-2016 Total Questions - 2

• question_answer1) A wire of length 2 units is cut into two parts  which are bent respectively to form a square of side = x units and a circle of radius = r units. If the sum of the areas of the square and the circle so formed is minimum, then : [JEE Main Solved Paper-2016 ]
  A)
  \[2x=r\]                               
  done clear
  B)
  \[2x=(\pi +4)r\]
  done clear
  C)
  \[(4-\pi )x=\pi r\]            
  done clear
  D)
  \[x=2r\]
  done clear
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• question_answer2) Consider \[f(x)={{\tan }^{-1}}\left( \sqrt{\frac{1+\sin x}{1-\sin x}} \right),x\in \left( 0,\frac{\pi }{2} \right).\] A normal to \[y=f(x)at\,x=\frac{\pi }{6}\]also passes through the point : [JEE Main Solved Paper-2016 ]
  A)
  \[\left( \frac{\pi }{4},0 \right)\]                 
  done clear
  B)
  \[\left( 0,\text{ }0 \right)\]
  done clear
  C)
  \[\left( 0,\frac{2\pi }{3} \right)\]                               
  done clear
  D)
  \[\left( \frac{\pi }{6},0 \right)\]
  done clear
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