# Solved papers for JEE Main & Advanced JEE Main Paper (Held On 11 April 2015)

### done JEE Main Paper (Held On 11 April 2015)

• question_answer1) $A+2B+3C\rightleftharpoons A{{B}_{2}}{{C}_{3}}$ Reaction of 6.0 g of $A,6.0\times {{10}^{23}}$atoms of B, and 0.036 mol of C yields 4.8 g of compound $A{{B}_{2}}{{C}_{3}}.$If the atomic mass of A and C are 60 and 80 amu, respectively, the atomic mass of B is (Avogadro no.$=6\times {{10}^{23}}$) : [JEE Main Online Paper (Held On 11 April 2015)]

A)  70 amu

B)  60 amu

C)  50 amu

D)  40 amu