Solved papers for JEE Main & Advanced AIEEE Solved Paper-2006

done AIEEE Solved Paper-2006 Total Questions - 3

• question_answer1) The molar conductivities \[\hat{\ }_{NaOAc}^{o}\]and \[\hat{\ }_{HCl}^{o}\]at infinite dilution in water at\[25{}^\circ C\]are 91.0 and \[426.2\text{ }S\text{ }c{{m}^{2}}/mol\]respectively. To calculate \[\hat{\ }_{HOAc'}^{o}\]the additional value required is     AIEEE  Solved  Paper-2006
  A)
  \[\hat{\ }_{{{H}_{2}}O}^{o}\]                     
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  B)
         \[\hat{\ }_{KCl}^{o}\]                    
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  C)
         \[\hat{\ }_{NaOH}^{o}\]              
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  D)
         \[\hat{\ }_{NaCl}^{o}\]
  done clear
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• question_answer2) Given the data at\[25{}^\circ C,\] \[Ag+{{I}^{-}}\xrightarrow{{}}AgI+{{e}^{-}};\]                     \[E{}^\circ =0.152\text{ }V\] \[Ag\xrightarrow{{}}A{{g}^{+}}+{{e}^{-}};\]                     \[E{}^\circ =-0.800\text{ }V\] What is the value of\[\log \text{ }{{K}_{sp}}\]for\[AgI\]? \[\left( 2.303\frac{RT}{F}=0.059\,V \right)\]     AIEEE  Solved  Paper-2006
  A)
  \[\text{ }8.12\]                 
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  B)
         \[+\text{ }8.612\]            
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  C)
         \[-37.83\]                           
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  D)
  \[-16.13\]
  done clear
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• question_answer3) Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1 M is\[100\text{ }\Omega \]. The conductivity of this solution is\[1.29\text{ }S\text{ }{{m}^{-1}}\].Resistance of the same cell when filled with 0.2 M of the same solution is\[520\,\Omega \]The molar conductivity of 0.02 M solution of the electrolyte will be     AIEEE  Solved  Paper-2006
  A)
  \[124\times {{10}^{-4}}S\,{{m}^{2}}\text{ }mo{{l}^{-1}}\]
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  B)
  \[1240\times {{10}^{-4}}S\,{{m}^{2}}mo{{l}^{-1}}\]
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  C)
  \[1.24\times {{10}^{-4}}S\,{{m}^{2}}mo{{l}^{-1}}\]
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  D)
  \[12.4\times {{10}^{-4}}S\,{{m}^{2}}mo{{l}^{-1}}\]
  done clear
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