JCECE Medical JCECE Medical Solved Paper-2015

  • question_answer
    Arrange the following events of the replication of DNA.
    (i) Bonds between complementary bases breaks.
    (ii) Bonds between complementary bases forms.
    (iii) DNA molecules uncoils.
    (iv) Opposite strands separates.
    (v) Sugar phosphate bonds forms.
    (VI) Free nucleotides align with the complementary nucleotides on each strand.
    Choose the correct alternative

    A)  \[VI\to I\to III\to IV\to V\to II\]

    B)  \[III\to VI\to IV\to V\to II\]

    C)  \[I\to III\to VI\to IV\to II\to V\]

    D)  \[III\to I\to IV\to VI\to II\to V\]

    Correct Answer: D

    Solution :

     Events in DNA replication DNA molecule uncoils \[\to \] bonds between complementary base pairs breaks \[\to \] opposite strands separate \[\to \] free nucleotide along with complementary nucleotide on each side \[\to \]bond between complementary base pair forms \[\to \]sugar phosphate bond forms.


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