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JCECE Medical JCECE Medical Solved Paper-2015

  • question_answer
    The radius of divalent cation \[{{\text{M}}^{\text{2+}}}\] is 94 pm and  that of divalent anion \[{{\text{X}}^{2-}}\]is 146 pm. Thus \[{{M}^{2+}}{{X}^{2-}}\] has

    A) \[\text{NaCl}\]structure      

    B)  linear structure

    C)  \[\text{CsCl}\]structure      

    D)  \[\text{ZnS}\]structure

    Correct Answer: A

    Solution :

     For \[{{\text{M}}^{2+}}{{X}^{-2}}\] \[\frac{{{r}_{+}}}{{{r}_{-}}}=\frac{94}{146}=0.6438\] Since, the radius ratio is in between 0.414 to  0.732, it has NaCI strcuture.


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