A and B are respectively.
A) \[{{H}_{2}}/Pt;LiAl{{H}_{4}}/{{H}_{2}}O\]
B) \[{{H}_{2}}/Pt;{{H}_{2}}/Pt\]
C) \[LiAl{{H}_{4}}/{{H}_{2}}O;LiAl{{H}_{4}}/{{H}_{2}}O\]
D) \[LiAl{{H}_{4}}/{{H}_{2}}O;{{H}_{2}}/Pt\]
Correct Answer: D
Solution :
\[\text{LiAl}{{\text{H}}_{\text{4}}}\]does not attack \[\text{(C=0)}\] bond, whereas\[{{\text{H}}_{\text{2}}}\text{/Pt}\] reduced it into\[(-C-OH).\]
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