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JCECE Medical JCECE Medical Solved Paper-2015

  • question_answer
    The binding energy per nucleon of \[{{C}^{12}}\]is\[{{E}_{1}}\] and that of \[{{C}^{13}}\] is \[{{E}_{2}}.\] The energy required to remove one neutron from \[{{C}^{13}}\]is

    A)  \[12{{E}_{1}}+12{{E}_{2}}\]

    B)  \[13{{E}_{2}}-12{{E}_{1}}\]

    C)  \[12{{E}_{2}}-13{{E}_{1}}\]

    D)  \[13{{E}_{2}}+12{{E}_{1}}\]

    Correct Answer: B

    Solution :

     Binding energy of \[{{C}^{12}}\]is \[B{{E}_{1}}=12\times {{E}_{1}}\] Binding energy of \[{{C}^{13}}\]is \[B{{E}_{2}}=13\times {{E}_{2}}\] Thus, energy required to remove one neutron from \[{{C}^{13}}\]is \[\Delta E=B{{E}_{2}}-B{{E}_{1}}=13{{E}_{2}}-12{{E}_{1}}\]


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