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JCECE Medical JCECE Medical Solved Paper-2014

  • question_answer
    A stone is thrown vertically upwards. When the stone is at a height equal to half of its maximum height its speed will be 10 m/s, then the maximum height attained by the stone is (Take\[g=10\,m/{{s}^{2}}\])

    A)  3 m              

    B)  15 m

    C)  1 m              

    D)  10 m

    Correct Answer: D

    Solution :

     Let u be the initial velocity and h be the maximum height attained, by the stone \[{{v}_{1}}^{2}={{u}^{2}}-2gh,\] \[{{(10)}^{2}}={{u}^{2}}-2\times 10\times \frac{h}{2}\] \[100={{u}^{2}}-10h\] ?(i) Again at height h \[{{v}_{2}}^{2}={{u}^{2}}-2gh\] \[{{(0)}^{2}}={{u}^{2}}-2\times 10\times h\] \[{{u}^{2}}=20h\] So, from Eqs. (i) and (ii), we have \[100=10h\] \[h=10\,m\]


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