A) \[{{\sin }^{-1}}(0.01)\]
B) \[{{\sin }^{-1}}(0.0001)\]
C) \[{{\sin }^{-1}}(0.001)\]
D) \[{{\sin }^{-1}}(0.1)\]
Correct Answer: C
Solution :
In Youngs double slit experiment half angular width is given by \[\sin \theta =\frac{\lambda }{d}\] \[\sin \theta =\frac{589\times {{10}^{-9}}}{0.589\times {{10}^{-3}}}={{10}^{-3}}\] \[\theta ={{\sin }^{-1}}(0.001)\]
You need to login to perform this action.
You will be redirected in
3 sec
