JCECE Medical JCECE Medical Solved Paper-2014

  • question_answer
    A particle of mass \[{{m}_{1}}\]moves with velocity\[{{\upsilon }_{1}}\]  and collides with another particle at rest of equal mass. The velocity of the second particle after the elastic collision is                     

    A) \[3{{v}_{1}}\]

    B)  \[{{v}_{1}}\]

    C)  \[-{{v}_{1}}\]

    D)  \[0\]

    Correct Answer: B

    Solution :

     For elastic collision \[{{v}_{2}}=\left( \frac{{{m}_{2}}-{{m}_{1}}}{{{m}_{1}}+{{m}_{2}}} \right){{u}_{2}}+\frac{2{{m}_{1}}{{u}_{1}}}{{{m}_{1}}+{{m}_{2}}}\] Because another body is initially at rest i.e., \[{{u}_{2}}=0\] Velocity of the second particle \[{{v}_{2}}=\frac{2{{m}_{1}}{{v}_{1}}}{2{{m}_{1}}}\] \[\left( \begin{align}   & \because \,{{u}_{1}}={{v}_{1}} \\  & {{m}_{2}}={{m}_{1}} \\ \end{align} \right)\] \[{{v}_{2}}={{v}_{1}}\]


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