A) \[7.94g\,m{{L}^{-1}}\]
B) \[8.96\text{g}\,\text{m}{{\text{L}}^{-1}}\]
C) \[2.78\text{g}\,\text{m}{{\text{L}}^{-1}}\]
D) \[6.72\text{g}\,\text{m}{{\text{L}}^{-1}}\]
Correct Answer: A
Solution :
\[d=\frac{ZM}{{{N}_{A}}{{a}^{3}}}\](for bcc, \[Z=2\]) \[{{d}_{Fe}}=\frac{(2)\times 56.0\,g\,mo{{l}^{-1}}}{(6.02\times {{10}^{23}}mo{{l}^{-1}}){{(2.861\times {{10}^{-8}})}^{3}}c{{m}^{3}}}\] \[=7.94\,g\,M{{L}^{-1}}\]
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