A) \[HSO_{4}^{-}\]
B) \[N{{a}_{2}}C{{O}_{3}}\]
C) \[N{{H}_{3}}\]
D) \[O{{H}^{-}}\]
Correct Answer: A
Solution :
\[\text{HSO}_{4}^{-}\]can accept proton to form \[{{\text{H}}_{\text{2}}}\text{S}{{\text{O}}_{\text{4}}}\]and also give a proton to form \[SO_{4}^{2-}\]therefore, it acts both as Bronsted acid as well as base.
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