A) \[h\]
B) \[c\]
C) \[\frac{1}{h}\]
D) \[\frac{1}{c}\]
Correct Answer: B
Solution :
We have\[{{\lambda }_{e}}=\frac{h}{mv}\]and \[{{\lambda }_{P}}=\frac{h}{mc}\] According to the question, \[{{\lambda }_{e}}={{\lambda }_{P}}\] \[\therefore \] \[v=c\] \[\frac{{{E}_{p}}}{{{P}_{e}}}=\frac{m{{c}^{2}}}{mv}=\frac{{{c}^{2}}}{c}=c\]
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