JCECE Medical JCECE Medical Solved Paper-2013

  • question_answer
    4L of 0.02 M aqueous solution of NaCI was diluted by adding 1 L of water. The molality of  the resultant solution is

    A)  0.004 

    B)  0.008

    C)  0.012                 

    D)  0.016

    Correct Answer: D

    Solution :

     \[{{M}_{1}}{{V}_{1}}={{M}_{2}}{{V}_{2}}\] Or \[0.02\times 4={{M}_{2}}\times 5\] or \[{{M}_{2}}=0.016\]


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