A) 2.87BM
B) 3.87 BM
C) 3.47 BM
D) 3.67 BM
Correct Answer: B
Solution :
\[C{{r}^{3+}}=3{{d}^{3}};\] Hence, \[C{{r}^{3+}}=3{{d}^{3}};\] \[Bm=\sqrt{3(3+2)}=\sqrt{15}=3.87\,BM\]
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