A) 30 N
B) 40 N
C) 72 N
D) 400 N
Correct Answer: C
Solution :
Given, \[{{m}_{2}}=10\,kg;\,{{m}_{1}}=30g.{{v}_{1}}=400\,m/s\] Number of bullets fired/second = 6 \[F=?\] We know, F = rate of change of linear momentum \[\therefore \] \[F=\frac{\text{change}\,\text{in}\,\text{linear}\,\text{momentum}}{\text{time}}\] In \[t=1\text{ }s,\]total mass of bullets fired \[=30\times 6=180\text{ }g\] \[=180\times {{10}^{-3}}kg\] So, \[F=\frac{180\times {{10}^{-3}}\times 400}{1}=72\,N\]
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