question_answer

\[{{C}_{6}}{{H}_{6}}+C{{l}_{2}}(excess)\frac{Anhy.AlC{{l}_{3}}}{dark,cold}P\] Product, P is

A) \[{{C}_{6}}{{H}_{5}}Cl\]

B)  \[{{C}_{6}}{{H}_{4}}C{{l}_{2}}\]

C)  \[{{C}_{6}}{{H}_{6}}C{{l}_{6}}\]

D)  \[{{C}_{6}}C{{l}_{6}}\]

Correct Answer: D

Solution :

 Benzene on treatment with excess of chlorine in the presence of anhydrous \[\text{AlC}{{\text{l}}_{\text{3}}}\]in dark yields hexachlorobenzene.