A) \[C{{N}^{-}},{{O}_{3}}\]
B) \[Cl{{O}_{2}},Br{{F}_{2}}\]
C) \[Br{{O}^{-}}_{2},BrF_{2}^{+}\]
D) \[lC{{l}_{2}},Cl{{O}_{3}}\]
Correct Answer: C
Solution :
Both \[BrO_{2}^{-}(35+2\times 8+1=52)\] and \[BrF_{2}^{+}(35+2\times 9-1=52)\]have 52 electrons.
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