A) 1 and 0
B) 0 and 1
C) -1 and 0
D) -1 and 1
Correct Answer: C
Solution :
For a perfectly diamagnetic substance \[B={{\mu }_{0}}(H+l)=0\] \[\Rightarrow \] \[l=-H\] \[\therefore \] \[{{\chi }_{m}}=\frac{l}{H}=-1\] and \[{{\mu }_{r}}=1+{{\chi }_{m}}\] \[=1-1=0\] \[\therefore \] \[\mu ={{\mu }_{0}}{{\mu }_{r}}=0\]
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