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JCECE Medical JCECE Medical Solved Paper-2012

  • question_answer
    Equilibrium constants \[{{K}_{1}}\]and \[{{K}_{2}}\]for the following equilibria \[NO(g)+\frac{1}{2}{{O}_{2}}N{{O}_{2}}(g)\] and \[2N{{O}_{2}}(g)2NO(g)+{{O}_{2}}(g)\]are related as

    A)  \[{{K}_{2}}=\frac{1}{{{K}_{1}}}\]

    B)  \[{{K}_{2}}={{K}_{1}}^{2}\]

    C)  \[{{K}_{2}}=\frac{{{K}_{1}}}{2}\]

    D)  \[{{K}_{2}}=\frac{1}{={{K}_{1}}^{2}}\]

    Correct Answer: B

    Solution :

    (i) \[NO(g)+\frac{1}{2}{{O}_{2}}(g)N{{O}_{2}}(g)\] So, \[{{K}_{1}}=\frac{[N{{O}_{2}}]}{[NO]{{[{{O}_{2}}]}^{1/2}}}\] ?(i) (ii) \[2N{{O}_{2}}(g)2NO+{{O}_{2}}(g)\] So, \[{{K}_{2}}=\frac{{{[NO]}^{2}}[{{O}_{2}}]}{{{[N{{O}_{2}}]}^{2}}}\] ?(ii) From Eq. (i) \[{{K}_{1}}^{2}=\frac{{{[N{{O}_{2}}]}^{2}}}{{{[NO]}^{2}}[{{O}_{2}}]}\] or \[\frac{1}{K_{1}^{2}}=\frac{{{[NO]}^{2}}[{{O}_{2}}]}{{{[N{{O}_{2}}]}^{2}}}\] ?(iii) From Eqs. (i) and (iii) \[{{K}_{2}}=\frac{1}{K_{1}^{2}}\]


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